Two metal spheres, each of radius 2.0 cm, have a center-to-center separation of

Question

Two metal spheres, each of radius 2.0 cm, have a center-to-center separation of 1.0 m. Sphere 1 has charge +1.50 times 10^8 C. Sphere 2 has charge of -4.40 times 10^8 C. Assume that the separation is large enough for us to assume that the charge on each sphere is uniformly distributed (the spheres do not affect each other). Take V = 0 at infinity. Calculate the potential at the point halfway between the centers. V Calculate the potential on the surface of sphere 1. V Calculate the potential on the surface of sphere 2. V A metal sphere of radius 35 cm has a net charge of 8.0 times 10^8 C. What is the electric field at the sphere's surface? N/C If V = 0 at infinity, what is the electric potential at the sphere's surface? V At what distance from the sphere's surface has the electric potential decreased by 600 V? m

Explanation / Answer

22.

A. Electric field at the surface of sphere is given by

E = kq/r^2

r = radius of sphere = 35 cm = 0.35 m

q = 8*10^-8 C

E = 9*10^9*8*10^-8/0.35^2

E = 5877.55 N/C

B. electric potential at the surface of sphere is given by

V = kq/r

V = 9*10^9*8*10^-8/0.35

V = 2057.14 V

C.

given that V= 600 V

find r = ?

r = kq/V

r = 9*10^9*8*10^-8/600

r = 1.2 m

let me know if you have any doubt.

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