An object undergoes simple harmonic motion along an x axis with a period of 0.70

Question

An object undergoes simple harmonic motion along an x axis with a period of 0.70 s and amplitude of 27 mm . Its position is x = 18 mm when t = 0.

Equation of motion is x(t)=Asin(t+i)

Part A:

Determine the value for A in the equation of motion. Suppose that A>0.

Part B:

Determine value for in the equation of motion. Suppose that >0.

Part C:

Determine all the possible values of i in the equation of motion. Suppose that <i

If there is more than one answer enter your answers in ascending order separated by commas.

Explanation / Answer

A) amplitude A = 27 mm = 0.027 m

B) w = 2*pi/T = 2*3.142/0.7 = 8.977 rad/s

C) at t = 0

x(0) = A*sin(wt+phi)

18 mm = 27 mm*sin(phi)

sin(phi) = 18/27 = 0.667

phi = 0.729 rad or 41.835 degrees

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