An electric field of strength E 7400 N/C is directed along the +X-axis as shown

Question

An electric field of strength E 7400 N/C is directed along the +X-axis as shown A proton is initially at rest at point A. What is the magnitude of the force on the proton due to the electric field? Submit Answer Tries 0/2 What is the magnitude of the acceleration of the proton? m/s Submit Answer Tries 0/2 What is the work done by the electric field on the proton after it has moved a distance of 2 cm from point A to point B? Submit Answer Tries 0/2 What is the kinetic energy of the proton at this instant? Submit Answer Tries 0/2 What is the speed (magnitude of the velocity) of the proton at this instant? m/s Submit Answer Tries 0/2

Explanation / Answer

a)

A proton is placed in a uniform electric field of 7400 N/C.

the magnitude of the electric force felt by the proton = F = qE

F = 1.6022 x 10^-19 x 7400

F = 1.1856 x 10^-15 N

b)

F = ma

a = F/m

a = (1.1856 x 10^-15 N) / (1.67 x 106-27)

a = 7.1 x 10^11 m/s^2

c)

W = qEd

W = 1.6022 x 10^-19 x 7400 x 0.02

W = 2.37 x 10^-17 J

Not sure about last two options

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