Two identical 18.8-kg balls, each 28.4 cm in diameter, are suspended by two 35.0

Question

Two identical 18.8-kg balls, each 28.4 cm in diameter, are suspended by two 35.0-cm wires as shown in the figure (Figure 1) . The entire apparatus is supported by a single 18.0-cm wire, and the surfaces of the balls are perfectly smooth.

Part A

Find the tension in the top wire.

368

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Correct

Part B

Find the tension in each of two bottom wires.

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Part C

T= N

Two identical 18.8-kg balls, each 28.4 cm in diameter, are suspended by two 35.0-cm wires as shown in the figure (Figure 1) . The entire apparatus is supported by a single 18.0-cm wire, and the surfaces of the balls are perfectly smooth.

Part A

Find the tension in the top wire.

368

SubmitMy AnswersGive Up

Correct

Part B

Find the tension in each of two bottom wires.

SubmitMy AnswersGive Up

Incorrect; One attempt remaining; Try Again

Part C

How hard does each ball push on the other one?

T= N

Explanation / Answer

Distance from attachment point to centre of each ball = (35 + 14.2) = 49.2 cm.
Distance from each ball to the centre of the ball = 14.2 cm. (the radius).
Total normal weight of system = (18.8 x 2) x 9.8 = 368.48 N.

Halve it, as both masses are equal, and the angles from normal of both suspending wires are equal.

(368.48/2) = 184.24 N.
Sin angle from normal of each wire = (14.2/49.2), Angle = 16.78 degrees.

184.24 N/(cos 16.78) = 192.4 N. tension in each wire.
Sqrt(192.4^2 - 184.24^2) = 55.5 N. each ball applies to the other.

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