A 2.10 mm -diameter glass bead is positively charged. The potential difference b
ID: 1591134 • Letter: A
Question
A 2.10 mm -diameter glass bead is positively charged. The potential difference between a point 2.10 mm from the bead and a point 4.40 mm from the bead is 500 V .
What is the charge on the bead?
Express your answer with the appropriate units.
Item 7 Part A A 2.10 mm -diameter glass bead is positively charged. The potential difference between a point 2.10 mm from the bead and a point 4.40 mm from the bead is 500 V What is the charge on the bead? Express your answer with the appropriate units. LA alue Units aie Submit My Answers Give UpExplanation / Answer
we may consider the bead as the point size particle
potential at the 2.1 mm is V1 = k*q/r1 = (9*10^9*q)/(2.1*10^-3) = 4.28*10^12*q
potetial at 4.4 mm is V2 = k*q/r2 =(9*10^9*q)/(4.4*10^-3) = 2.045*10^12*q
then potential difference is V2-V1 = (2.045*q - 4.28*q)*10^12 = 500
q = -223.71*10^-12 C = -0.223 nC
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