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A 2.10 mm -diameter glass bead is positively charged. The potential difference b

ID: 1591134 • Letter: A

Question

A 2.10 mm -diameter glass bead is positively charged. The potential difference between a point 2.10 mm from the bead and a point 4.40 mm from the bead is 500 V .

What is the charge on the bead?

Express your answer with the appropriate units.

Item 7 Part A A 2.10 mm -diameter glass bead is positively charged. The potential difference between a point 2.10 mm from the bead and a point 4.40 mm from the bead is 500 V What is the charge on the bead? Express your answer with the appropriate units. LA alue Units aie Submit My Answers Give Up

Explanation / Answer


we may consider the bead as the point size particle

potential at the 2.1 mm is V1 = k*q/r1 = (9*10^9*q)/(2.1*10^-3) = 4.28*10^12*q


potetial at 4.4 mm is V2 = k*q/r2 =(9*10^9*q)/(4.4*10^-3) = 2.045*10^12*q

then potential difference is V2-V1 = (2.045*q - 4.28*q)*10^12 = 500

q = -223.71*10^-12 C = -0.223 nC

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