A 2.10- c m -high insect is 1.50 m from a 127- m m -focal-length lens. Where is

Question

A 2.10-cm-high insect is 1.50m from a 127-mm-focal-length lens. Where is the image? Follow the sign conventions. Express your answer to three significant figures and include the appropriate units. How high is the image? Follow the sign conventions. Express your answer to three significant figures and include the appropriate units.
What type is the image? real, upright virtual, inverted virtual, upright real, inverted


A 2.10-cm-high insect is 1.50m from a 127-mm-focal-length lens. Where is the image? Follow the sign conventions. Express your answer to three significant figures and include the appropriate units. How high is the image? Follow the sign conventions. Express your answer to three significant figures and include the appropriate units.
What type is the image? real, upright virtual, inverted virtual, upright real, inverted

How high is the image? Follow the sign conventions. Express your answer to three significant figures and include the appropriate units.
What type is the image? real, upright virtual, inverted virtual, upright real, inverted real, upright virtual, inverted virtual, upright real, inverted real, upright virtual, inverted virtual, upright real, inverted real, upright virtual, inverted virtual, upright real, inverted


real, upright virtual, inverted virtual, upright real, inverted

Explanation / Answer

1/v+1/u = 1/f

1/v + 1/1.5 = 1/.127

v = 0.138 m

magnification m = -v/u = 0.092

height of the image = -2.10*0.092 = -0.193 cm

image will be real and inverted

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.