An electron is moving through a magnetic field whose magnitude is 8.40 times 10^

Question

An electron is moving through a magnetic field whose magnitude is 8.40 times 10^-4. T. The electron experiences only a magnetic force and has an acceleration of magnitude 3.60 times 10^14 m/s^2. At a certain instant, it has a speed of 7.00 times 10^6 m/s. Determine the angle theta (less than 90 degree) between the electron's velocity and the magnetic field. The drawing shows a straight wire carrying a current I. Above the wire is a rectangular loop that contains a resistor R. If the current I is decreasing in time, what is the direction of the induced current through the resistor R-left-to-right or right-to-left? If the induced current goes from left to right through the resistor, type the letters "LTR" in the box below. If the current goes from right to left through the resistor, type the letters "RTL" in the box. Direction of induced current =

Explanation / Answer

Q9.

magnetic force=charge*speed*magnetic field*sin(theta)

==>mass*acceleration=charge*speed*magnetic field*sin(theta)

==>sin(theta)=9.1*10^(-31)*3.6*10^14/(1.6*10^(-19)*7*10^6*8.4*10^(-4))=0.34821

theta=20.378 degrees

Q10.

field due to the current carrying wire is into the plane of the paper.

as current is decreasing, the field is decreasing in the direction of into the page of the paper.

so the induced current will be such that the field will be along the direction of into the page of paper.

so the current through R is in clockwise direction i.e. from left to right.

so answer is : LTR

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.