Chapter 04, Problem 082 GO To hoist himself Into a tree, a 72.0-kg man ties one

Question

Chapter 04, Problem 082 GO To hoist himself Into a tree, a 72.0-kg man ties one end of a nylon rope around his waist and throws the other end over a branch of the tree. He then pulls downward on the free end of the rope with a force of 369 N. Neglect any friction between the rope and the branch, and determine the man's upward acceleration. Use g-9.80 m/sec the tolerance is +/-6% Click if you would like to Show Work for this question: Open Show Work estion Assistance, you will learn while you earn points based on the Point Potential Pollicv set bw vnur Instrnartor

Explanation / Answer

Given that

the mass of man is m = 72 kg

           Upward tention is T = 369 N

        From Newons second law T - mg = ma

a = ( T / m - g )

put values

a =369 N / 72 kg - 9.8m/s2

. a=5.125-9.8 m/s^2

calculate

a= -4.67m/s2 Answer

        This is the mansupward accelaration.

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