A particle of mass 6.57 × kg, moving at 3.17 × m/s,strikes an identical particle

Question

A particle of mass 6.57 × kg, moving at 3.17 × m/s,strikes an identical particle which is initially at rest. After theinteraction, the particles (which can't be distinguished) areobserved moving at angles 79.4° and 10.6°, both anglesbeing measured with respect to the original direction of motion.What are the final speeds of the particles

please try to be as detailed as possible :D

Explanation / Answer

Given that    m1 = m2 = m = 6.57 x kg    u1 = 3.17 x m/s    u2 = 0    1 = 79.4 degree    2 = 10.6 degree    v1 = ?    v2 = ? Applying Conservation of momentum along the x-axis wehave      m1 * u1 = m1 * v1 cos1 + m2 *v2 cos2 ==> u1 = v1 * cos1 + v2 *cos2        ......1 Along the vertical direction we have                v1 * sin1 =v2 * sin2       ........2 Solve eq 1 and 2 and substitute values , then you get thevalues of v1 and v2.

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