An 95.0-N crate of apples sits at rest on a ramp that runs from the ground to th

Question

An 95.0-N crate of apples sits at rest on a ramp that runs from the ground to the bed of a truck. The ramp is inclined at 18.0° to the ground.
(a) What is the normal force exerted on the crate by the ramp?
N

(b) The interaction partner of this normal force has what magnitude and direction?
Magnitude N
Direction ° below the horizontal

It is exerted by what object on what object?


Is it a contact or a long-range force?


(c) What is the static frictional force exerted on the crate by the ramp?
N

(d) What is the minimum possible value of the coefficient of static friction?


(e) The normal and frictional forces are perpendicular components of the contact force exerted on the crate by the ramp. What is the magnitude and direction of the contact force?
Magnitude N
Direction ° above the horizontal

Explanation / Answer

the weight of the crate W = 95N the angle of inclination of ramp ? = 180 a)the normal force on crate Fn= Wcos? Fn = 95cos18 =95*0.9511 = 90.35N b)the interaction force of normal force is frictional force Fs = Wsin? Fs= 95 sin 18 = 95*0.3090 = 29.35 N it is the force exerted by the surface of ramp on crate. it is a contact force. c)the static friction acts on the crate Fs=Wsin?=29.35N d)the minimum possiable of cofficient of static friction µs=tan? µs=tan18 = 0.3249 e)the magnitude of contact force is equals to weight of crate = 95N it is opposite to the direction weight.

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