Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

An 95.0-N crate of apples sits atrest on a ramp that runs from the ground to the

ID: 1667761 • Letter: A

Question

An 95.0-N crate of apples sits atrest on a ramp that runs from the ground to the bed of a truck. Theramp is inclined at 24.0° to theground. (a) What is the normal force exerted on the crate by the ramp?____N (b) The interaction partner of this normal force has whatmagnitude and direction? Magnitude is 86.8 N, in what direction? ____ degrees belowhorizontal (c) What is the static frictional force exerted on the crateby the ramp? (d) What is the minimum possible value of the coefficient ofstatic friction? (e) The normal and frictional forces are perpendicularcomponents of the contact force exerted on the crate by the ramp.What is the magnitude and direction of the contact force? Magnitude ____N Direction ____ degrees above horizontal


An 95.0-N crate of apples sits atrest on a ramp that runs from the ground to the bed of a truck. Theramp is inclined at 24.0° to theground. (a) What is the normal force exerted on the crate by the ramp?____N (b) The interaction partner of this normal force has whatmagnitude and direction? Magnitude is 86.8 N, in what direction? ____ degrees belowhorizontal (c) What is the static frictional force exerted on the crateby the ramp? (d) What is the minimum possible value of the coefficient ofstatic friction? (e) The normal and frictional forces are perpendicularcomponents of the contact force exerted on the crate by the ramp.What is the magnitude and direction of the contact force? Magnitude ____N Direction ____ degrees above horizontal


Explanation / Answer

(a) the normal force exerted on the crate by theramp F1=95*cos24=86.8N (b) The interaction partner of this normal force hasMagnitude is 86.8N direction 660 below the horizontal (c) the static frictional force exerted on the crate by theramp F=mg*sin24=95*sin24=38.6 N (d)the minimum possible value of the coefficient of staticfriction F/(m*g*cos24)=F/86.6=0.445 (e) the magnitude  of the contact force (F12+F2)=95 N direction900 above horizontal
(e) the magnitude  of the contact force (F12+F2)=95 N direction900 above horizontal
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote