A beam of electrons that is traveling on a horizontal planefrom east to west wit

Question

A beam of electrons that is traveling on a horizontal planefrom east to west with a speed of 4.8x106m/s enters auniform vertical magnetic field pointing down. a) What is the magnitude of the magnetic field and thedirection of the force on an electron in this beam if it startsbending in a circular arc of diameter 1.45m? b)What would the speed of protons entering the same field tobend in a circle of the same radius as in part a? c)What would be the magnetic field if protons coming with4.8x104m/s speed and are bending in a circle of the sameradius as in part a? d)What would the radius of the circlus motion of the electronsin the beam if the magnetic field found in part a is doubled andthe initial speed is multiplies by 3? A beam of electrons that is traveling on a horizontal planefrom east to west with a speed of 4.8x106m/s enters auniform vertical magnetic field pointing down. a) What is the magnitude of the magnetic field and thedirection of the force on an electron in this beam if it startsbending in a circular arc of diameter 1.45m? b)What would the speed of protons entering the same field tobend in a circle of the same radius as in part a? c)What would be the magnetic field if protons coming with4.8x104m/s speed and are bending in a circle of the sameradius as in part a? d)What would the radius of the circlus motion of the electronsin the beam if the magnetic field found in part a is doubled andthe initial speed is multiplies by 3?

Explanation / Answer

F = qv × B but since they are perpendicular it becomesqvB also F=ma = m(v2/r) SO qvB=m(v2/r) qB=mv/r B=mv/rq = (9.11e-31)(4.8e6)/(1.45)(1.6e-19) = 1.88e-5 T using the right hand rule to figure out the direction of the force,we find that if we are looking at the compass then the force isdirected directly at us

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