An air-filled capacitor consists of two parallel plates, each withan area of 7.6

Question

An air-filled capacitor consists of two parallel plates, each withan area of 7.60 cm2, separated by a distance of1.80 mm. (a) If a 22.0 Vpotential difference is applied to these plates, calculate theelectric field between the plates.
1 kV/m

(b) What is the surface charge density?
2 nC/m2

(c) What is the capacitance?
3 pF

(d) Find the charge on each plate.
4 pC (a) If a 22.0 Vpotential difference is applied to these plates, calculate theelectric field between the plates.
1 kV/m

(b) What is the surface charge density?
2 nC/m2

(c) What is the capacitance?
3 pF

(d) Find the charge on each plate.
4 pC

Explanation / Answer

(a) the electric field between the plates
E = V/d = 12.2 kV/m
(b) the surface charge density =
E = /o
= oE = 108 nC/m2
(c) the capacitance
C = oA/d = 3.737 pF
(d) Q = A = 82.1 pC

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