Two particles with identical postive charges and a separationof 2.60x10^-2 m, ar

Question

Two particles with identical postive charges and a separationof 2.60x10^-2 m, are released from rest. Immediately after the release, particle 1 has an acceleration(a1) whose magnitude is 4.60x10^3 m/s, while particle 2 has anacceleration (a2) whose magnitude is 8.50x10^3 m/s^2. Particle 1 has a mass of 5.50x10^-6 kg. Find the charge on each particle: _____C Two particles with identical postive charges and a separationof 2.60x10^-2 m, are released from rest. Immediately after the release, particle 1 has an acceleration(a1) whose magnitude is 4.60x10^3 m/s, while particle 2 has anacceleration (a2) whose magnitude is 8.50x10^3 m/s^2. Particle 1 has a mass of 5.50x10^-6 kg. Find the charge on each particle: _____C

Explanation / Answer

r = 2.6m = 2.6 * 10-2 m a1 = 4.60 * 103 m/s2 a2 = 8.50 * 103 m/s2 m1 = 5.50 * 10-6 kg Using Coulombs law we know that force that acts on each particlehas magnitude given by: F = kq1q2/r2 Also, we know from Newtons third law of action and reaction thatforces acting on each body are going to be equal. Also, second Newtons law tells us that: F = ma So, F = m1a1andnow:kq1q2/r2=m1a1 The problem statement tells us that both charges are positive (theywill repel) and that they are equal, so q1 = q2 kq12/r2 =m1a1 q12 =r2m1a1/k q1 =(r2m1a1/k) q1 = r * (m1a1/k) q1 = q2 = ....plug in the values and thereyou are. I hope you got everything. Cheers.

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