An electric ceiling fan is rotating about a fixed axis with an initial angular v
ID: 1779030 • Letter: A
Question
An electric ceiling fan is rotating about a fixed axis with an initial angular velocity magnitude of 0.280 rev/s . The magnitude of the angular acceleration is 0.918 rev/s2 . Both the the angular velocity and angular accleration are directed clockwise. The electric ceiling fan blades form a circle of diameter 0.710 m .
Compute the fan's angular velocity magnitude after time 0.200 s has passed. Express your answer numerically in revolutions per second.
Through how many revolutions has the blade turned in the time interval 0.200 s from Part A? Express the number of revolutions numerically.
What is the tangential speed vtan(t) of a point on the tip of the blade at time t = 0.200 s ? Express your answer numerically in meters per second.
What is the magnitude a of the resultant acceleration of a point on the tip of the blade at time t = 0.200 s ? Express the acceleration numerically in meters per second squared.
Explanation / Answer
A)
Radius of fan blade=r=0.355 m
The initial angular velocity of fan=wi=0.280
rev/s=0.280*2pi radian/s.
The angular acceleration = a! = 0.918 rev/s^2.=0.918*2pi radian/s^2
time 't'=0.200 s
angular velocity after 0.200 s
wf=wi+a!t
wf = 0.280*2pi +.0.918*2pi *0.2
wf= 2.9128 rad/s
wf=0.4636 rev./s
B)
number of revolutions=N=angular displacement O/2pi
angular displacement O=[(wf+wi)/2 ]t=[0.3718]*2pi*0.2=0.07436*2pi radian
number of revolutions=N=O/2pi=0.07436
C)
tangential speed v=r*wf =0.355*2.9128=1.034044 m/s
D)
resultant acceleration is vector sum of centripetal acceleration and tangential acceleration
centripetal acceleration= Ac =r(wf)^2= 3.01196 m/s^2
tangential acceleration= At=r*a = 0.355*5.7679=2.0476 m/s^2
resultant acceleration = sq rt [Ac^2+At^2] = 3.6420 m/s^2
resultant acceleration of a point on the tip at 0.200 s is 3.6420 m/s^2
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