A particle of mass 0.500 kg is shot from P as shown in Figure P7.6. The particle

Question

A particle of mass 0.500 kg is shot from P as shown in Figure P7.6. The particle has an initial velocity with v_i, a horizontal component of 30.0 m/s. The particle rises to a maximum height of 20.0 m above P. Using the law of conservation of energy, determine (a) the vertical component of v_j, (b) the work done by the gravitational force on the particle during its motion from P to B, and (c) the horizontal and the vertical components of the velocity vector when the particle reaches B?. The work done from P to max height.

Explanation / Answer

Here ,

mass , m = 0.50 Kg

vh = 30 m/s

h = 20 m

a) Now ,let the vertical component is vy

Using conservation of energy

0.5 * m * vy^2 = m * g * h

0.5 * vy^2 = 9.8 * 20

vy = 19.8 m/s

the vertical component of Vi is 19.8 m/s

b)

work done by gravitational force = m * g * 60

work done by gravitational force = 0.50 * 9.8 * 60

work done by gravitational force = 294 J

c)
at the point B

horizontal component = 30 m/s

vertical component = sqrt(19.8^2 + 2 * 9.8 * 60)

vertical component = 39.6 m/s

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