A car is traveling around a horizontal circular track with radius r-280m at a co

Question

A car is traveling around a horizontal circular track with radius r-280m at a constant speed v 27 m's as shown The angle 8A -39 above the x axis, and the angle 8p-51° below the x axis 1) What is the magnitude of the cars acceleration? m/s Submit 2) What is the x component of the cars acceleration when it is at point A ms2 Submit 3) What is the y component of the car's acceleration when it is at point A m/s2 Submit 4) What is the x component of the cars acceleration when it is at point B m/s2 Submit 5) What is the y component of the cars acceleration when it is at point B m/s2 Submit 6) As the car passes point B, the y component of its acceleration is O increasing O constant Odecreasing Submit

Explanation / Answer

Part A)

acceleration = v2/r = (27)2/(280) = 2.60 m/s2

Part B)
x component is

ax = (2.60)*(cos 39) = 2.02 m/s2 (In the negative x direction answer key may want this answer as -2.02 m/s2)

Part C)

y component is

ay = (2.60)(sin 39) = 1.63 m/s2

Part D)

x component is

ax = (2.60)*(cos 51) = 1.63 m/s2 (In the negative x direction answer key may want this answer as -1.63 m/s2)

Part E)

y component is

ay = (2.60)*(sin 51) = 2.02 m/s2

Part F)

Decreasing

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