A 123.4N carton is pulled up a frictionless baggage ramp inclined at 33.0 degree

Question

A 123.4N carton is pulled up a frictionless baggage ramp inclined at 33.0 degrees above the horizontal by a rope exerting a 70.0N pull parallel to the ramp's surface. The carton travels 5.55m along the surface of the ramp. Calculate the work done on the carton by the rope. Express your answer using three significant figures. Calculate the work done on the carton by the gravity. Express your answer using three significant figures. Calculate the work done on the carton by the normal force of the ramp. Express your answer using three significant figures. What is the net work done on the carton? Express your answer using two significant figures. Suppose that the rope is angled at 45.8^circ above the horizontal, instead of being parallel to the ramp's surface. How much work does the rope do on the carton in this case? Express your answer using three significant figures.

Explanation / Answer

The work done on the carton by the rope is fdcos = 70*5.55*1 = 389 J.

The work done on the carton by (the) gravity is fdcos = -123.4*5.55*cos(57) = -373 J (negative sincegravity opposes the direction moved).

The work done on the carton by the normal force is fdcos = 0. Trick question. The normal force, which is normal to the direction of motion, never does work.

The net work done on the carton is 389 - 373 = 26 J (the carton's kinetic energy).

With the rope at 45.8 degrees, the work the rope does on the carton is 70*5.55*cos(12.5 degrees) = 379 J.

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