The equilibrium solution y = -6 is unstable, y = 0 is semistable and y = 6 is un

Question

The equilibrium solution y = -6 is unstable, y = 0 is semistable and y = 6 is unstable, f(y) = y(36 - y2). The equilibrium solution y = -6 is asymptotically stable, y = 0 is semistable and y = 6 is unstable, f(y) = y(36 - y2). The equilibrium solution y = -6 is asymptotically stable, y = 0 is unstable and y = 6 is asymptotically stable, f(y) = y(36 - y2). Sketch the graph of f (y) versus y, determine the critical (equilibrium) points, and classify each one as asymptotically stable, unstable, or semistable. dy/dt= y(36 - y2), - infinity

Explanation / Answer

Option C is the answer according to the graph.

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