At t = 0, a 795 g mass at rest on the end of a horizontal spring (k = 120 N/m) i

Question

At t = 0, a 795 g mass at rest on the end of a horizontal spring (k = 120 N/m) is struck by a hammer, which gives the mass an initial speed of 2.80 m/s.
(a) Determine the period of the motion. (sec)
(b) Determine the frequency of the motion. (Hz)
(c) Determine the amplitude. (m)
(d) Determine the maximum acceleration. (m/sec^2)
(e) Determine the position as a function of time.
(____ m) sin[(___ rad/sec)t]
(e) Determine the total energy. (J)

From what I hear, this stuff is pretty straight foreward, but our teacher never taught us, and the book is completely useless. Thanks

Explanation / Answer

a . T = 2 * pi * sqrt ( m / k ) T = 2 * pi * sqrt ( 0.795 / 120 ) = 0.5114 s ;

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