An air puck of mass 0.028 kg is tied to a string and allowed to revolve in a cir

Question

An air puck of mass 0.028 kg is tied to a string and allowed to revolve in a circle of radius 1.5 m on a frictionless horizontal surface. The other end of the string passes through a hole in the center of the surface, and mass of 2.0 kg is tied to it. The suspended mass remains in equilibrium while the puck revolves on the surface. Accerelation of gravity is 9.81 m/s^2.
a.) What is the magnitude of the force that maintains circular motion acting on the puck? Answer in units of N.
b.) What is the puck's linear speed? Answer in units of m/s.

Explanation / Answer

( a )

the centripetal force and weight balance

centripetal force = mg = 2 * 9.8 = 19.6 N <-----------ans

( b )

m1 v^2 / r = mg ;

m1 is the revolving mass ;

0.028 * v^2 / r = 2 * g ;

0.028 * v^2 / 1.5 = 2 * 9.8 ;

v = 32.403 m /s   <-----------ans

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