A series circuit consists of an ac source of variable frequency, a 115 resistor,
ID: 2021252 • Letter: A
Question
A series circuit consists of an ac source of variable frequency, a 115 resistor, a 1.25 F capacitor, and a 4.50 mH inductor.
a)Find the impedance of this circuit when the angular frequency of the ac source is adjusted to the resonance angular frequency.
Z=_____________________
b)Find the impedance of this circuit when the angular frequency of the ac source is adjusted to twice the resonance angular frequency.
Z=_____________________
c)Find the impedance of this circuit when the angular frequency of the ac source is adjusted to half the resonance angular frequency.
Z=_____________________
Explanation / Answer
resonance frequency f = 1 / 2LC = 1 / {(2)(3.14)(4.5*10-3 H)(1.25*10-6 F)} = 2123.14 Hz a) at resonance XL = XC impedance of this circuit is Z = {R2 + (XL - XC)2} Z = {R2 + (XC - XC)2} Z = R = 115 b) if frequency is twice , f' = 2f = 4246.28 Hz inductive reactance XL = 2f'L = (2)(3.14)(4246.28 Hz)(4.5*10-3 H) = 120 capacitive reactance XC = 1/2f'C = 1 / (2)(3.14)(4246.28 Hz)(1.25*10-6 F) = 30 impedance of this circuit is Z = {R2 + (XL - XC)2} = {(115 )2 + (120 - 30 )2} = 146.03 c) if frequency is half, f'' = f/2 = 1061.57 Hz inductive reactance XL = 2f''L = (2)(3.14)(1061.57 Hz)(4.5*10-3 H) = 30 capacitive reactance XC = 1/2f''C = 1 / (2)(3.14)(1061.57 Hz)(1.25*10-6 F) = 120 impedance of this circuit is Z = {R2 + (XL - XC)2} = {(115 )2 + (30 - 120 )2} = 146.03 inductive reactance XL = 2f'L = (2)(3.14)(4246.28 Hz)(4.5*10-3 H) = 120 capacitive reactance XC = 1/2f'C = 1 / (2)(3.14)(4246.28 Hz)(1.25*10-6 F) = 30 impedance of this circuit is Z = {R2 + (XL - XC)2} = {(115 )2 + (120 - 30 )2} = 146.03 c) if frequency is half, f'' = f/2 = 1061.57 Hz inductive reactance XL = 2f''L = (2)(3.14)(1061.57 Hz)(4.5*10-3 H) = 30 capacitive reactance XC = 1/2f''C = 1 / (2)(3.14)(1061.57 Hz)(1.25*10-6 F) = 120 impedance of this circuit is Z = {R2 + (XL - XC)2} = {(115 )2 + (30 - 120 )2} = 146.03 Z = {R2 + (XL - XC)2} = {(115 )2 + (120 - 30 )2} = 146.03 c) if frequency is half, f'' = f/2 = 1061.57 Hz inductive reactance XL = 2f''L = (2)(3.14)(1061.57 Hz)(4.5*10-3 H) = 30 capacitive reactance XC = 1/2f''C = 1 / (2)(3.14)(1061.57 Hz)(1.25*10-6 F) = 120 impedance of this circuit is Z = {R2 + (XL - XC)2} = {(115 )2 + (30 - 120 )2} = 146.03 inductive reactance XL = 2f''L = (2)(3.14)(1061.57 Hz)(4.5*10-3 H) = 30 capacitive reactance XC = 1/2f''C = 1 / (2)(3.14)(1061.57 Hz)(1.25*10-6 F) = 120 impedance of this circuit is Z = {R2 + (XL - XC)2} = {(115 )2 + (30 - 120 )2} = 146.03 capacitive reactance XC = 1/2f''C = 1 / (2)(3.14)(1061.57 Hz)(1.25*10-6 F) = 120 impedance of this circuit is Z = {R2 + (XL - XC)2} = {(115 )2 + (30 - 120 )2} = 146.03 Z = {R2 + (XL - XC)2} = {(115 )2 + (30 - 120 )2} = 146.03Related Questions
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