Two 360-n (R) resistors (right) are connected in series with a source emf. A 635

Question

Two 360-n (R) resistors (right) are connected in series with a source emf. A 6350 V with internal 3.23 V. is connected across R r You Ans the following and reads V L may wer questions. coming use symbol l out from the battery if a) Express the equivalent resistance Rav of the part of the circuit made of the b) voltmeter and using the symbol c) Express the total resistance of circuit using the symbol R and r (5 points) d) Express emf using the symbol v,R and r. (15 points) Calculate the numerical value for emf E. (5 points)

Explanation / Answer

Part A)

1/REQ = 1/R + 1/r

Which can be rearranged to say REQ = Rr/(R+r)

Part B)

Total resistance equals the REQ from part A, plus R

Total REQ = Rr/(R+r) + R

That can also be rearranged to show

REQ = (2Rr + R2)/(R+r)

Part C)

Using Ohm's Law

V = IR

V = (I)(2Rr + R2)/(R+r)

Part D)

The value of the current can be calculated from the readings in the Voltmeter.

The equavalent resistance of that portion of the circuit is

Rr/(R+r) = (360)(6350)/(360 + 6350) = 340.68

The voltage across that part is given as 3.23 V

Therefore I = 3.23/340.68

I = 9.48 mA

That is the current for the total circuit so...

V = IR

The total REQ = (2Rr + R2)/(R+r) = [(2)(360)(6350) + (360)2]/(360 + 6350) = 700.68

V = (9.48 X 10-3)(700.68)

V = 6.64 V

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