A 10000 {\ m N} car comes to a bridge during a storm and finds the bridge washed

Question

A 10000 { m N} car comes to a bridge during a storm and finds the bridge washed out. The 650 { m N} driver must get to the other side, so he decides to try leaping it with his car. The side the car is on is 24.0 { m m} above the river, while the opposite side is a mere 6.40 { m m} above the river. The river itself is a raging torrent 63.0 { m m} wide.How fast should the car be traveling just as it leaves the cliff in order to clear the river and land safely on the opposite side?.What is the speed of the car just before it lands safely on the other side

Explanation / Answer

using h = ut + at^2/2

24 - 6.40 = 0 + 9.8 x t^2/2

t = 0.948 sec

so v t = 63

v = 63/0.948 = 66.46 m/s

after vx = v = 66.46 m/s .....ans

vy = gt = 9.8 x 0.948=9.29 m/s

v = sqrt(vx^2 + vy^2) = 67.11 m/s ......ans

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