A 2.00 kg pumpkin oscillates from a vertically hanging light spring once every 0

Question

A 2.00 kg pumpkin oscillates from a vertically hanging light spring once every 0.54 s. Calculate the equation giving the pumpkin's position y (+ upward) as a function of time t, assuming it started by being compressed 11 cm from the equilibrium position (where y = 0), and released. (Use the following as necessary: t. Assume t is in s and y is in m.) y= How long will it take to get to the equilibrium position for the first time? s What will be the pumpkin's maximum speed? m/s What will be its maximum acceleration, and where will that first be attained? m/s2

Explanation / Answer

a> y=0.11cos(11.6t) b>0.27s c>v=1.276m/s d>14.8m/s^2 at extreme

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