An electric point charge of Q1 = 5.45 nC is placed at the origin of the real axi

Question

An electric point charge of Q1 = 5.45 nC is placed at the origin of the real axis. Another point charge of Q2 = 3.55 nC is placed at a position of p = 2.50 m on the real axis. At which position can a third point charge of q = -5.89 nC be placed so that the net electrostatic force on it is zero?

Let the sign of Q2 be changed from positive to negative. At which position can the point charge q be placed now so that the net electrostatic force on it is zero?

Explanation / Answer

a)5.45/x^2 = 3.55/(2.5-x)^2 =>(2.5-x)^2 = 0.651376147x^2 =>2.5-x = 0.807078774x, 2.5-x = -0.807078774x =>1.807078774x = 2.5, 0.192921226x = 2.5 =>x = 1.383448268m, 12.95865699m But cannot be equal to 12.95865699m Therefore x = 1.383448268m b)There will be no change. That is x = 1.383448268m

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