A uniform electric field with a magnitude of 1400 N/C points in the negative x -

Question

A uniform electric field with a magnitude of 1400 N/C points in the negative x-direction, as shown in the figure below. A particle with a mass of 3.5 g and a charge of -0.045

A uniform electric field with a magnitude of 1400 N/C points in the negative x-direction, as shown in the figure below. A particle with a mass of 3.5 g and a charge of -0.045 µC is released from rest at point A. (a) In which direction will this charge move? 1. positive y-direction 2. negative x-direction 3. negative y-direction 4. positive x-direction (b) What speed will it have after moving through a distance of 5.0 cm? The electric field has a magnitude of 1400 N/c. ____________cm/s (c) Suppose the particle continues moving for another 5.0 cm. Will its increase in speed for the second 5.0 cm be greater than, less than, or equal to its increase in speed in the first 5.0 cm? 1. greater than less than 2. equal to

Explanation / Answer

Positive charges move in the direction of electric field. Negative charges move opposite to direction of the field.

The particle moves in positive x direction.

F = qE

   = 0.045 * 10 -6 * 1400

a = F/M = (0.045 * 10-6 * 1400)/3.5 * 10-3

   = 0.018

V2 = U2 + 2as

     = 2*0.018*5

     = (0.18)0.5

V = 0.42 cm/s

It will cover next 5cm quickly because now inital velocity is 0.42 cm/s previously initial velocity was 0. It will take lesser time to cover next 5cm thus change in speed will be less

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