Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

e6eMiwuzg 4 dia e.pee_ Filum blanks in the data and make the indi- 0.1168 Temper

ID: 229741 • Letter: E

Question

e6eMiwuzg 4 dia e.pee_ Filum blanks in the data and make the indi- 0.1168 Temperature, r 21 C 294.1c 0.3522 Temperature, T Barometric pressure 751 mm Hg of empty beaker 1412g Vapor pressure of H,O at t (Appendix 1) mm Hg Man of heaker plus displaced water 388.3 g Pressure of dry H Mass of displaced water Volume of displaced water density 1.00 g/mL) mL Pressure of dry H2 Volume. V. of H" Volume of displaced water --mL; --liters in atm, Tin K, R-0.0821 liter Find the number of moles of H, evolved, s, (Eq. 5; V in liters, Pi, atm/mole K). moles H Find , the number of moles of H, per gram of sample , Im) moles Hy find the % Al in the sample from the graph prepared for Problem 1. %Al Find the % Al in the sample by using Equation 11. SAI 31

Explanation / Answer

From the given data,

Temperature (T) = 294.15 K

Vapor pressure of water at 294.15 K = 18.7 mmHg

Pressure of dry H2 = 751 - 18.7 = 732.3 mmHg

Pressure of dry H2 in atm (P) = 732.3/760 = 0.963 atm

Volume of H2 (V) = 247.1 ml = 0.2471 L

R = gas constant

Using ideal gas equation,

moles of H2 (n) = PV/RT

                          = 0.963 x 0.2471/0.08205 x 294.15

                          = 0.00986 moles

moles of H2/gram sample = 0.00986 moles/0.2354 g = 0.042 mol/g