What mass of oxygen is needed to react with 7.25 gal of methanol according to th

Question

What mass of oxygen is needed to react with 7.25 gal of methanol according to the balanced equation below? (1.00 gal = 3.79 L, and the density of methanol is 0.793 g/mL.)

2 CH3OH(l) + 3 O2(g) 2 CO2(g) + 4 H2O(g)
If appropriate, express your answer in scientific notion. What mass of oxygen is needed to react with 7.25 gal of methanol according to the balanced equation below? (1.00 gal = 3.79 L, and the density of methanol is 0.793 g/mL.)

2 CH3OH(l) + 3 O2(g) 2 CO2(g) + 4 H2O(g)
If appropriate, express your answer in scientific notion.

Explanation / Answer

1.00 gal = 3.79 L so

7.25 gal = 27.5 L of methanol

27.5 L = 27500 mL

density = mass / volume

0.793 g/mL = mass / 27500 mL

mass of methanol = 21808 g

number of moles of methanol = 21808 / 32.04 g/mol = 681 mol

from the balanced equation we can say that

2 mole of methanol requires 3 mole of O2 so

681 mole of methanol will require

= 681 mole of methanol *( 3 mole of O2 / 2 mole of methanol )

= 1022 mole of O2

mass of 1 mole of O2 = 32.0 g

so the mass of 1022 mole of O2 = 32704 g

Therefore, the mass of O2 produced would be 32704 g

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