What mass of oxalic acid, H2C204, is required to prepare 250 mL of a solution th

Question

What mass of oxalic acid, H2C204, is required to prepare 250 mL of a solution that has a concentration of (4.83x10-1) M H2C204? Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: x10 10 Answer units Save Question 12 (10 points) Use the correct answer to the previous question to solve the following problem. What volume of 2.06 M KMn04 (MW 126.9 g/mol) contains (3.90x1042) g of solute? Note: Your answer is assumed to be reduced to the highest power possible. Your Answer x10 Answer units

Explanation / Answer

Answer:

Molar mass of Oxalic acid =126

Volume (V) = 25 mL

Concentration = 4.83 x 10-1 M

Molality = (mass/molar mass) x (1000 / volume in mL)

0.483 = (mass/126) x (1000/250)

0.483 = (mass/126) x (4)

0.483/4 =mass/ 126

0.1207 x 126 = mass

Mass = 15.214 g

Mass = 0.1521 x 10-2 g.

Question-12:

Answer:

molarity = 2.06 M

mlocelular weight (molar mass) = 126.9 g/mole

mass of the compound = 3.90 x 102 g = 390 g

Molality = (mass /mw) x (1000 / volume in mL)

2.06 = (390 /126.9) x (1000 / V)

V = (3.073 x 1000) / 2.06

V = 1491.747 L

V = 14.917 x 10-2 L

V = 0.14917 x 10-4 L

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