An object has two different forces acting on it. Force A is 89.8 N at an angle o

Question

An object has two different forces acting on it. Force A is 89.8 N at an angle of =25.7°. Force B is 29.8 N at an angle of =62.6°. Two vectors. FA is up and to the right. FB is down and to the left. What is the magnitude and direction of the x-component of Force A? to the left to the right Submit Answer Tries 0/10 What is the magnitude and direction of the x-component of Force B? to the left to the right Submit Answer Tries 0/10 What is the magnitude and direction of the x-component of the net force acting on the object? to the left to the righ

Explanation / Answer

Here ,

FA = 89.8 N

theta = 25.7 degree

FB = 29.8 N

phi = 62.6 degree

Now , for the x - component of A

x - component of A = 89.8 * cos(25.7) to the right

x - component of A = 80.9 N to the right

x - component of A is 80.9 N to the right

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for the x - compoenent of B

x - compoenent of B = 29.8 * cos(62.6)

x - compoenent of B = 13.71 to the left

x - compoenent of B is 13.71 to the left

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for the x-component of net force

x-component of net force = x - compoenent of B + x - compoenent of A

x-component of net force = 80.9 - 13.71 to the right

x-component of net force = 67.2 N to the right

x-component of net force is 67.2 N to the right

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