The customer service department for a wholesale electronics outlet claims that 8

ID: 3239312 • Letter: T

Question

The customer service department for a wholesale electronics outlet claims that 85 percent of all customer complaints are resolved to the satisfaction of the customer. In order to test this claim, a random sample of 15 customers who have filed complaints is selected.

Find each of the following if we assume that the claim is true: (Do not round intermediate calculations. Round final answers to 4 decimal places.)

Suppose that of the 15 customers selected, 9 have had their complaints resolved satisfactorily. Using part b, do you believe the claim of 85 percent satisfaction? Explain.

Explanation / Answer

Answer to part b)

We got P = 0.85

n = 15

i) P( x 13) = We use binomal probability function to find this value

I have made use of excel commands to find this probability

=BINOMDIST(13,15,0.85,1)

We get : P( x 13) = 0.6814

ii) P(x > 10)

the excel comman would be

=1-BINOMDIST(10,15,0.85,1)

We get P(x > 10) = 0.9383

iii) P(X >=14)

The excel command is

=1-binomdist(13,15,0.85,1)

We get P(X >=14) = 0.3186

iv) P(9 x 12) = P(x =9) + P(x=10) + P(x=11) + P(x=12)

Formula of P(X=9) is =binomdist(9,15,0.85,0)

we get P(x =9) = 0.0132

Formulaa of P(x=10) is =binomdist(10,15,0.85,0)

We get P(x=10) = 0.045

Formula for P(x=11) is =binomdist(11,15,0.85,0)

we get P(x=11) = 0.1156

Formula of P(x=12) is =binomdist(12,15,0.85,0)

we get P(x=12) = 0.2184

Thus P(9 x 12) = 0.0132 + 0.045 + 0.1156 + 0.2184

P(x 9 x 12) = 0.3922

v. P(x 9)

The formula for it is

=binomdist(9,15,0.85,1)

We get P(x 9) = 0.01681

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The customer service department for a wholesale electronics outlet claims that 8

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