The customer service department for a wholesale electronics outlet claims that 8
ID: 3254032 • Letter: T
Question
The customer service department for a wholesale electronics outlet claims that 85 percent of all customer complaints are resolved to the satisfaction of the customer. In order to test this claim, a random sample of 15 customers who have filed complaints is selected.
Find each of the following if we assume that the claim is true: (Do not round intermediate calculations. Round final answers to 4 decimal places.)
Suppose that of the 15 customers selected, 9 have had their complaints resolved satisfactorily. Using part b, do you believe the claim of 85 percent satisfaction? Explain.
The customer service department for a wholesale electronics outlet claims that 85 percent of all customer complaints are resolved to the satisfaction of the customer. In order to test this claim, a random sample of 15 customers who have filed complaints is selected.
Explanation / Answer
Answer to part b)
We got P = 0.85
n = 15
.
i) P( x 13) = We use binomal probability function to find this value
I have made use of excel commands to find this probability
=BINOMDIST(13,15,0.85,1)
We get : P( x 13) = 0.6814
.
ii) P(x > 10)
the excel comman would be
=1-BINOMDIST(10,15,0.85,1)
We get P(x > 10) = 0.9383
.
iii) P(X >=14)
The excel command is
=1-binomdist(13,15,0.85,1)
We get P(X >=14) = 0.3186
.
iv) P(9 x 12) = P(x =9) + P(x=10) + P(x=11) + P(x=12)
Formula of P(X=9) is =binomdist(9,15,0.85,0)
we get P(x =9) = 0.0132
.
Formulaa of P(x=10) is =binomdist(10,15,0.85,0)
We get P(x=10) = 0.045
.
Formula for P(x=11) is =binomdist(11,15,0.85,0)
we get P(x=11) = 0.1156
.
Formula of P(x=12) is =binomdist(12,15,0.85,0)
we get P(x=12) = 0.2184
.
Thus P(9 x 12) = 0.0132 + 0.045 + 0.1156 + 0.2184
P(x 9 x 12) = 0.3922
.
v. P(x 9)
The formula for it is
=binomdist(9,15,0.85,1)
We get P(x 9) = 0.01681
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