A operator + (const A& otherObject) const; |Overloading Operators| What the mean

Question

A operator + (const A& otherObject) const;

|Overloading Operators|
What the meaning of the & and the two const?
A A::operator + (const A& otherObject) const {
} In this function def why do we need the class name twice? A A::operator? A operator + (const A& otherObject) const;

|Overloading Operators|
What the meaning of the & and the two const?
A A::operator + (const A& otherObject) const {
} In this function def why do we need the class name twice? A A::operator?

|Overloading Operators|
What the meaning of the & and the two const?
A A::operator + (const A& otherObject) const { A A::operator + (const A& otherObject) const {
} In this function def why do we need the class name twice? A A::operator?

Explanation / Answer

A operator + (const A& otherObject) const;

in this function declaration A is the return type of function.Now in defination outside the class

A A::operator + (const A& otherObject) const

{

}

we use :: (resolution operator) with Class name A. Because function (operator +) is member of A, when referring to it from outside the class, we have to qualify their names.  If we had not put the A:: qualification on the names, we would be defining some new functions in the global scope, rather than as members of A.

And another A in defination is return type of function.

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