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Application of Partial Pressures You have just landed on a new planet and are re

ID: 480894 • Letter: A

Question

Application of Partial Pressures

You have just landed on a new planet and are responsible for analyzing the composition of the atmosphere. After collecting a sample of the atmosphere and analyzing it, you discover that the total atmospheric pressure is 540 mmHg. Using your knowledge of partial pressures, fill out the table below. Assume that the water vapor pressure is the same as on Earth.
Match the numbers with their appropriate slots.

Part J Application of Partial Pressures You have just landed on a new planet and are responsible for a the composition of the atmosphere. After collecting a sample of the atmosphere and analyzing it, you discover that the total atmospheric pressure is 540 mmHg. Using your knowledge of partial pressures, fill out the table below. Assume that the water vapor pressure is the same as on Earth. Match the numbers with their appropriate slots. Drag the appropriate labels to their respective targets. Note: not all labels will be used. 0.15 mmHg 119 mmHg 0.17 mmHg 408 mmHg Atmospheric pressure 540 mmHg Gas Percentage of gas 108 mmHg 25C, 100% humidity 25C, dry air 24 mmHg air Nitrogen (N2) 0 mmHg 21% oxygen (02) 446 mmHg Carbon Dioxide (CO2 0.03% Water vapor 427 mmHg 0.16 mmHg 47 mmHg 113 mmHg help

Explanation / Answer

Let us consider each case

i) Dry air,

We know that the relation between partial pressure and mole fraction is

Partial pressure = mole fraction X total pressure of mixture of gases

As given

Mole fraction of nitrogen = 0.79

Partial pressure of nitrogen = 0.79 X 540 mmHg = 426.6 mmHg

Mole fraction of oxygen = 0.21

Partial pressure of oxygen = 0.21 X 540 = 113.4 mmHg

Mole fraction of CO2 = 0.0003

Partial pressure of CO2 = 0.0003 X 540 = 0.162 mmHg

(ii) Humid air

The pressure of water vapour = 23.8 mmHg

So the pressure of dry air = 540 - 23.8 = 516.2 mmHg

Partial pressure = mole fraction X total pressure of mixture of gases

As given

Mole fraction of nitrogen = 0.79

Partial pressure of nitrogen = 0.79 X 516.2 mmHg = 407.798 mmHg

Mole fraction of oxygen = 0.21

Partial pressure of oxygen = 0.21 X 516.2= 108.402 mmHg

Mole fraction of CO2 = 0.0003

Partial pressure of CO2 = 0.0003 X 516.2 = 0.155 mmHg

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