Complete the stoichiometry table using the starting values provided. mass (g) mm

Question

Complete the stoichiometry table using the starting values provided. mass (g) mmoles equivalents density vol molecular reagent (g/mL) (mL) weight 2.174 bromobenzene 0.560 3.56 157.01 1.5 .373 magnesium 1.243 24.305 benzophenone 182.2 diethyl ether 21.239 4.12 theoretical product triphenylmethanol melting point of triphenylmethanol (°C) Select the name of the catalyst used for this reaction, if there was no catalyst used, select none In your lab notebook, you should complete the written portion of the prelab which includes a title, date, reaction equation, reagent table and plan of procedure. u l confirm that I have read the terms of the Ohio State University Department of Chemistry and Biochemistry Undergraduate organic Chemistry Laboratory prelab/postlab submission system and agree to the policies and procedures therein. Submit

Explanation / Answer

For Mg

Equivalent = 2.174

(3.56 x 1.243)/2.174 = 2.035 m moles = 0.002035 moles

Molar mass of Mg = 24.305 g/mol

Mass of Mg = number of moles x molar mass.

                    = 0.002035 moles x 24.305 = 0.0495 g

For benzophenone –

Molar mass of benzophenone = 182.2 g/mol

Equivalent = 1

(3.56 x 1.0)/2.174 = 1.638 m moles = 0.001638 moles

Mass of benzophenone = number of moles x molar mass.

                    = 0.001638 moles x 182.2 = 0.298 g

For ether-

Density of ether = 0.7133 g/ml

Molar mass of ether = 74.12 g/mol

Equivalent = 21.239

(3.56 x 21.239)/2.174 = 34.78 m moles = 0.03478 moles

Mass of ether = number of moles x molar mass.

                    = 0.03478 moles x 74.12 = 2.578 g

Volume of ether = 3.61ml.

Let the Ph = C6H6

PhBr + Mg PhMgBr

Ph2C=O+PhMgBrPh3COMg Br

Ph3COMg Br + H+Ph3COH+Mg2++Br

Calculate the limiting reactant (all molar ratios are 1:1)

Since benzophenone has the fewest moles, it is the limiting reactant. It will form 0.001638 mol of triphenylmethanol.

Calculate the theoretical yield.

The molar mass of Ph3COH is 260.3 g/mol. So

Theoretical yield = 0.001638 mol PhCOH×260.3 g Ph3COH/1mol Ph3COH

                              = 0.426g Ph3COH

Triphenylmethanol Melting point = 2620C

Magnesium ribbon and iodine catalyst

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