Calculate the zero point energy of^1H^127 I and^2 H^127 I given that the force c

Question

Calculate the zero point energy of^1H^127 I and^2 H^127 I given that the force constant is 291 N/m. If the potential energy minimum E_min is -294.7 kJ/mol for both cases what is the dissociation energies E_diss of each of these molecules? Using the results of Q2 assume that a chemical reaction depends on the dissociation of these molecules such that the rate constant k follows the Arrhenius formula k = A middot exp(-E_diss/RT) What is the ratio of the rate constants of these two molecules? (You can evaluate the ratio at T 300 K) This difference in the rate constants is known as the kinetic isotope effect.

Explanation / Answer

Given data:

Constant forcaF = 291 N/m.

Potential energy Emin = -294.7 Kj/mol

Dissociation energies Ediss = ?

Given molecule = H

The bond dissociation energies indicate the energy required to break a specific bond in a particular molecule, whereas the average bond energies are calculated from a set of experimental data assuming that all C-H bonds have the same energy.

Then H > H+

The dissociation of H = 104

3)Arrhenius formula K = A exp(-E diss/RT)

Then K = A exp(-104/8.3*300)

            = A exp(-0.04176)

      K/A = exp(-0.04176)

      K/A = log(-0.04176)

     K/A = 1.379

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.