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I was able to solve for questions 1 and 2, however I\'m having some trouble on n

ID: 513088 • Letter: I

Question

I was able to solve for questions 1 and 2, however I'm having some trouble on number 3. What would be the major differences at 321nm and 515nm? I guess it has something to do with the A= ecl equation? Thanks in advance! 1. points) ermine the molar absorptivity of the acidic form of bromocresol green at 445 nm and at 615 nm. Show your calculations below. These should also appear in the appropriate cells in the spreadsheets you will also prepare (see manual). Mass of b cres Vorong/L 0.0Ag/L x 10 Molar mass of bro Cresol 618.0 g/n lo o x 10 IS At 6 2. (1 point) Determine the molar absorptivity of the basic form of bromocresol green at 445 and at 615 nm. Show your calculations below. These values should also appear in the appropriate cells in your spreadsheets. O. OSS E e 23 91 L At 615 1.064 A no la N abs. ftivih 3. (1 point) What would have been the outcome of these experiments if the wavelengths chosen were 321 nm and 515 nm?

Explanation / Answer

Molar absorptivity of a compound is different at different wavelengths. If you choose a different wavelength, the value of concentration of acidic and basic form will be different

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