The rate of a certain reaction is given by the following rate law: rate = k [NO!

Question

The rate of a certain reaction is given by the following rate law: rate = k [NO! "o, Use this information to answer the questions below What is the reaction order in NO? 2 What is the reaction order in O2? What is overall reaction order? At a certain concentration of NO and O2, the initial rate of reaction is 0.810 M/S. What would the initial rate of the reaction be if the concentration of NO were doubled? Round your answer to 3 significant digits. The rate of the reaction is measured to be 4.0 x 105 M/S when [NO] = 1.1 M and [02] = 1.0 M. Calculate the value of the rate constant.Round your answer to 2 significant digits. | M-2 s-1 k 1 Don't Know Submit

Explanation / Answer

rate law is:
rate = k [NO]^2 [O2]
1)
order of NO = power of NO = 2
Answer: 2

2)
order of O2 = power of O2 = 1
Answer: 1

3)
overall order = sum of all orders
= 2 + 1
= 3
Answer: 3

4)
Given Rate law is:
rate = k[NO]^2[O2]
rate new / rate old = ([NO]new/[NO]old)^2*([O2]new/[O2]old)
here:
[NO]new/[NO]old = 2
[O2]new/[O2]old = 1
putting values
rate new / rate old = (2.0)^2*(1.0)
rate new / rate old = 4
rate new / 0.81 = 4
rate new = 3.24 M/s
Answer: 3.24 M/s

5)
rate = k [NO]^2 [O2]
4.0*10^5 M/s = k (1.1 M)^2 * (1.0 M)
k = 3.6*10^5 M-2.s-1
Answer: 3.6*10^5 M-2.s-1

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