An electron is the coordinate (x; y) = (0; 1) nm. A proton is at the coordinate

Question

An electron is the coordinate (x; y) = (0; 1) nm. A proton is at the coordinate (x; y) = (0;-1) nm:

(a) What is the force that these two particles exert on a proton at location (x; y) = (1; 0) nm? What is the force that these two particles exert on an electron at location (x; y) = (1; 0) nm?

(b) What is the force that these two particles exert on a helium nucleus at location (x; y) = (1; 0) nm? (c)What is the force that these two particles exert on a neon nucleus at location (x; y) = (1; 0) nm? (d)What is the force that these two particles exert on a xenon nucleus at location (x; y) = (1; 0) nm?

Explanation / Answer

The magnitude of force between proton and electron is:

F= k q1q2 /r2

F= k q1q2 / (sqrt (x2+y2))

F= 9x109 x(1.6x10-19)2/ (sqrt((1x10-9)2+(-1x10-9)2)2

here charge of electron and proton is same

F = 2.304x10-28 / 2x10--18

F=1.152x10-10 N

similar way u can calculate for other parts also.

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