An electron is the coordinate (x;y) = (0;1) nm. A proton is at the coordinate (x
ID: 586444 • Letter: A
Question
An electron is the coordinate (x;y) = (0;1) nm. A proton is at the coordinate (x;y) = (0; 1) nm: (a) What is the force that these two particles exert on a proton at location (x; y) = (1; 0) nm? What is the force that these two particles exert on an electron at location (x; y) = (1; 0) nm? (b) What is the force that these two particles exert on a helium nucleus at location (x; y) = (1; 0) nm? What is the force that these two particles exert on a helium nucleus at location (x; y) = (1; 0) nm? (c)What is the force that these two particles exert on a neon nucleus at location (x; y) = (1; 0) nm? What is the force that these two particles exert on a neon nucleus at location (x; y) = (1; 0) nm? (d)What is the force that these two particles exert on a xenon nucleus at location (x; y) = (1; 0) nm? What is the force that these two particles exert on a xenon nucleus at location (x; y) = (1; 0) nm?
Explanation / Answer
a)
r = distance of each proton and electron from proton = sqrt ((1 - 0)2 + (0 - 1)2) = 1.41 m
Net force on the proton
Fnet = Fe - Fp = Force by electron - Force by proton = k q2/r2 - k q2 /r2 = 0 N
b)
r = distance of each proton and electron from electron = sqrt ((1 - 0)2 + (0 - 1)2) = 1.41 m
Net force on the proton
Fnet = Fe - Fp = Force by electron - Force by proton = k q2/r2 - k q2 /r2 = 0 N
c)
Q = charge on Helium
r = distance of each proton and electron from helium = sqrt ((1 - 0)2 + (0 - 1)2) = 1.41 m
Net force on the proton
Fnet = Fe - Fp = Force by electron - Force by proton = k qQ/r2 - k qQ /r2 = 0 N
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