Calculate the molality (m) of a 8570 g sample of a solution of thesolute hexane

Question

Calculate the molality (m) of a 8570 g sample of a solution of thesolute hexane dissolved in the solvent chloroform if the samplecontains 617 g of hexane.


Molar Mass (g/mol) CH3(CH2)4CH3 86.18 CHCl3 119.38 Density ( kg/L ) CH3(CH2)4CH3 0.6548 CHCl3 1.483 Name/Formula hexane CH3(CH2)4CH3 chlorofo Calculate the molality (m) of a 8570 g sample of a solution of thesolute hexane dissolved in the solvent chloroform if the samplecontains 617 g of hexane.


Molar Mass (g/mol) CH3(CH2)4CH3 86.18 CHCl3 119.38 Density ( kg/L ) CH3(CH2)4CH3 0.6548 CHCl3 1.483 Name/Formula hexane CH3(CH2)4CH3 chlorofo

Explanation / Answer

Here we use the formula :        Molality = no. of moles of solute/mass of solvent (inkgs)             No. of moles of solute (hexane) = mass/molar mass = 617/86 =7.17 moles                 Mass of solvent (chloroform) = 8570 gms = 8.57 kgs           Therefore, molality = 7.17/8.57 moles/kg = 0.84 moles/kg

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