What is the pressure of an oxygen sample in mm of mineral oil if its pressure is

Question

What is the pressure of an oxygen sample in mm of mineral oil if its pressure is 28.5 mm Hg in a barometer?
(d of mineral oil = 0.88 g/mL; d of Hg = 13.5 g/mL) Question 2 options:
A) 1.9 mm mineral oil
B) 15 mm mineral oil
C) 32 mm mineral oil
D) 380 mm mineral oil
E) 440 mm mineral oil
please show me the steps on how you did it , pleasssseeeeeee What is the pressure of an oxygen sample in mm of mineral oil if its pressure is 28.5 mm Hg in a barometer?
(d of mineral oil = 0.88 g/mL; d of Hg = 13.5 g/mL) What is the pressure of an oxygen sample in mm of mineral oil if its pressure is 28.5 mm Hg in a barometer?
(d of mineral oil = 0.88 g/mL; d of Hg = 13.5 g/mL)
A) 1.9 mm mineral oil
B) 15 mm mineral oil
C) 32 mm mineral oil
D) 380 mm mineral oil
E) 440 mm mineral oil
1.9 mm mineral oil 15 mm mineral oil 32 mm mineral oil 380 mm mineral oil 440 mm mineral oil please show me the steps on how you did it , pleasssseeeeeee
A) 1.9 mm mineral oil
B) 15 mm mineral oil
C) 32 mm mineral oil
D) 380 mm mineral oil
E) 440 mm mineral oil

Explanation / Answer

using the pressure equation
Pressure = density * gravity * height

gravity x density of the mineral oil x height of mineral oil filled in barometer
= gravity x density of Hg x height of Hg

= 9.8 x 0.88 x height of mineral oil
pressure = 9.8 x 13.5 x 28.5
therefore height of the oil in barometer = (9.8 * 13.5 * 28.5)/(9.8 * 0.88) = 437.22 mm mineral oil( roughly)

So correct answer is E) which is close to the answer

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