Chemistry problem.... detail solution pls ... A 5 mL pipet has graduation marks

Question

Chemistry problem.... detail solution pls

...

A 5 mL pipet has graduation marks every 0.1 mL, therefore it can be read to 2 decimal places. When a liquid is drawn to the 5 mL mark, it should dispense 5.00 mL of liquid. Suppose this pipet is calibrated by dispensing distilled water from the pipet at exactly the 5 mL mark into a preweighed dry flask. The dry flask weighs 10.5472 g empty, and 15.5733 g with the dispensed water (22 degree C). If the density of the water is 0.997770 g mL-1 at this temperature, what is the actual volume delivered by the pipet?

Explanation / Answer

Weight of dry flask: 10.5472 g

Weight of flask with water: 15.5733 g

Density of water: 0.997770 g/mL

Weight of water = Weight of flask with water - Weight of dry flask

               ?           = 15.5733 g - 10.5472 g

Weight of water = 5.0261 g

Density = (mass of solution in g) / (volume of solution in mL)

              = 5.0261 g / 0.997770 g/mL

Density = 5.0373 mL

Pipet can be read to two decimal places, so therefore, the actual volume delivered bt pipet is 5.04 mL.

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