Compound Ksp CaSO4 4.9 x 10^-5 CaCO3 8.7 x 10^-9 CaF2 4.0 x 10-11 Ca(OH)2 8.0 x

Question

Compound  Ksp

CaSO4         4.9 x 10^-5

CaCO3         8.7 x 10^-9

CaF2            4.0 x 10-11

Ca(OH)2       8.0 x 10^-6

Ca3(PO4)2   1.2x 10^-26

CaS              soluable

a) Identify the least soluable calcium compound.

b) Identify the most soluable silver comound.

c) Calculate the concentration of calcium ion present in a saturated solution of fluorite (CaF2).

d) calcu;ate the concentration of ferrous ion (fe+2) present in a saturated solutin of ironII carbonate (FeCO3), which has a Ksp nearly identical to fluorite.

e) rank the following silver salts in order from most to least soluable (1=most 4=least) determined by the amount of silver ions in solution for a saturated solution.

AgCl

AgBr

AgI

Ag2CO3

Explanation / Answer

The above given salts are of different natures.

Let the solubility = s in each case.

So, for CaSO4 and CaCO3, s^2 = Ksp

solubility = sqrt(Ksp)

For CaSO4, sqrt(4.9*10^-5) = 7*10^-3

for CaCO3 = sqrt ( 8.7*10^-9) = 9.327 * 10^-5

For, CaF2 and Ca(OH)2, 4s^3 = Ksp

Solubility = (Ksp / 4)^1/3

So, solubility of CaF2 = (4 *10^-11 / 4) ^1/3 = 2.154 * 10^-4

Soubility of Ca(OH)2 = (8*10^-6 / 4 ) ^1/3 = 12.6 * 10^-3

For, Ca3(PO4)2, 108s^5 = Ksp

solubility = (Ksp/108)^1/5

s = (1.2*10^-26 / 108) ^1/5 = 2.56 * 10^-6

Most soluble Calcium compound = Ca(OH)2

Least souble calcium compound = Ca3(PO4)2

Ca ions present in saturated solution of CaF2 = solubility = 2.514 * 10^-4

Ksp of FeCO3 = same as that of caF2 = 4*10^-11

Ksp = s^2

s = sqrt( Ksp) = 6.32*10^-6

RanK:

1) AgI

2)AgBr

3) AgCl

4) Ag2CO3

(There must be some numerical data given to quantify the order)

Hope this helps. please rate it the best. Thanks.

Ask if you have any doubts.

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