Calculate the mole fraction and partial pressure of each gas, and the total pres

Question

Calculate the mole fraction and partial pressure of each gas, and the total pressure in the tank.

A tank at is filled with of sulfur tetrafluoride gas and of dinitrogen monoxide gas. You can assume both gases behave as ideal gases under these conditions.

Calculate the mole fraction and partial pressure of each gas, and the total pressure in the tank.

A 8.00L tank at 6.99 degree C is filled with 11.7 g of sulfur tetrafluoride gas and 6.00 g of dinitrogen monoxide gas. You can assume both gases behave as ideal gases under these conditions. Calculate the mole fraction and partial pressure of each gas, and the total pressure in the tank.

Explanation / Answer

Molar Mass of sulfur tetrafluoride = 108 gm

Number of moles of sulfur tetrafluoride, n1 =mass/molar mass = 11.7/108 =0.1083 mol

Molar Mass of dinitrogen monoxide = 44 gm

Number of moles of dinitrogen monoxide,n2=mass/molar mass = 6/44 =0.1364 mol

Total number of moles, n =n1+n2 = 0.1083 + 0.1364 =0.2447 mol

use :

P*V=n*R*T

here T = 6.99 oC =(273+6.99)= 279.99 K

P*V=n*R*T

P*8 =0.2447 * (0.0821)*(279.99)

P= 0.703 atm

so, Total pressure = 0.703 atm

mole fraction of sulfur tetrafluoride = n1 /(n1+n2)=n1/n = 0.1083/0.2447 =0.443

partial pressure of sulfur tetrafluoride =mole fraction of sulfur tetrafluoride * total pressure

                                                             = 0.443* 0.703 =0.311 atm

mole fraction of dinitrogen monoxide = n2 /(n1+n2)=n2/n = 0.1364/0.2447 =0.557

partial pressure of dinitrogen monoxide =mole fraction of sulfur tetrafluoride * total pressure

                                                             = 0.557 * 0.703 =0.392 atm

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