Consider the reaction of S-3-bromobutane (where the stereocenter is in the \"S\"

Question

Consider the reaction of S-3-bromobutane (where the stereocenter is in the "S" configuration) with OH', which we will assume procedes through an SN2 process for this question. Which of the following statements is TRUE. The carbon-halogen bond will be broken by the attack of the nucleophile. The product of the reaction will be a 50/50 mixture of R-3-hexanol and S-3-hexanol The reaction will have two steps. The nucleophilic lone pair electrons on the OH" will attack in the second step of the reaction. A tertiary carbocation will form during this reaction

Explanation / Answer

Ans- when S-3-Bromobutane react with OH- if reaction will be SN2 type then reaction occurs only in one step and 5-membered transition state formed because of when OH- attack to the back side of the leaving group then C-Br bond will be weak and after that break. so obtion a is correct.

(a) the carbon halogen bond will be broken by the attack of the nucleophile.

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