What is the heat of reaction (heat of neutralization)? kj/mol Mass of calorimete

ID: 926377 • Letter: W

Question

What is the heat of reaction (heat of neutralization)? kj/mol Mass of calorimeter: 8.322 g

Mass of calorimeter plus inital NaOH: 58.72g

Final mass of calorimeter: 108.3g

Initial temperature of calorimeter: 20.70g

Final temperature of system: 27.60g

Change in temperature and intital NaOH: 6.900 C

Mass of initial 1.0 M NaOH: 50.39g

Mass of 1.0 M HCl added: 49.54g

Initial temperature of added acid: 22.50 C

Change in temperature HCl: 5.100 C

Calorimeter constant: 115.2 J/C (pretty high)

moles of NaOH (or HCl): how to calculate? Would you do grams over molar mass, or molarity times liter to get moles?

mass of NaOh(initial)= 50.39 g

molar mass of NaOH= 40 g.

no. of moles= mass/molar mass= 1.26 moles

initial temperature of system= 20.7 degrees

final= 27.60

change in temp.= 6.9 degree celcius.

q = mtotal x Cg x T

mtotal = mass(NaOH) + mass(HCl) = 50.39 + 49.54 = 99.93 g
Cg = 4.18 JoC-1g-1 (heat capacity of water produced)
T = Tf - Ti = 6.9

q = 99.93 x 4.18 x 6.9= 2882.18 J

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