What is the heat of reaction (heat of neutralization)? kj/mol Mass of calorimete

Question

What is the heat of reaction (heat of neutralization)? kj/mol Mass of calorimeter: 8.322 g Mass of calorimeter plus inital NaOH: 58.72g Final mass of calorimeter: 108.3g Initial temperature of calorimeter: 20.70g Final temperature of system: 27.60g Change in temperature and intital NaOH: 6.900 C Mass of initial 1.0 M NaOH: 50.39g Mass of 1.0 M HCl added: 49.54g Initial temperature of added acid: 22.50 C Change in temperature HCl: 5.100 C Calorimeter constant: 115.2 J/C (pretty high) moles of NaOH (or HCl): how to calculate? Would you do grams over molar mass, or molarity times liter to get moles?

Explanation / Answer

given

mass of calorimter = 8.322 g

also

mass of calorimeter + NaOH = 58.72 g

so

inital mass of NaOH = (mass of calorimeter + NaOH ) - mass of calorimeter

initial mass of NaOH = 58.72 - 8.322

initial mass of NaOH = 50.398 g

so

moles of NaOH = mass / molar mass

so

moles of NaOH = 50.398 / 40

moles of NaOH = 1.26

now

moles of HCl added = 49.54 / 36.45

moles of HCl added = 1.36

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