Calculate the number of moles of Ag+ in 5.00 mL of (4.51x10^-3) M AgNO3. Enter y
ID: 1042453 • Letter: C
Question
Calculate the number of moles of Ag+ in 5.00 mL of (4.51x10^-3) M AgNO3.Enter your answer with the correct number of sig figs when written in proper scientific notation. Calculate the number of moles of Ag+ in 5.00 mL of (4.51x10^-3) M AgNO3.
Enter your answer with the correct number of sig figs when written in proper scientific notation. Calculate the number of moles of Ag+ in 5.00 mL of (4.51x10^-3) M AgNO3.
Enter your answer with the correct number of sig figs when written in proper scientific notation.
Explanation / Answer
Number of moles AgNO3 = molarity * volume of solution in L
n = 4.51 * 10-3 * 5.00 / 1000
n = 2.26 * 10-5 mol of AgNO3
AgNO3 (aq.) -----------> Ag+ (aq.) + NO3- (aq.)
Moles of Ag+ = moles of AgNO3 = 2.26 * 10-5 mol
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